Koszul complex

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Short description: Construction in homological algebra

The Koszul complex is a concept in mathematics introduced by Jean-Louis Koszul.

Definition

Let A be a commutative ring and s: Ar → A an A-linear map. Its Koszul complex Ks is

rAr  r1Ar    1Ar  0ArA

where the maps send

α1αk  i=1k(1)i+1s(αi) α1α^iαk

where  ^ means the term is omitted and means the wedge product. One may replace Ar with any A-module.

Motivating example

Let M be a manifold, variety, scheme, ..., and A be the ring of functions on it, denoted 𝒪(M).

The map s : Ar → A corresponds to picking r functions f1,...,fr. When r = 1, the Koszul complex is

𝒪(M) f 𝒪(M)

whose cokernel is the ring of functions on the zero locus f = 0. In general, the Koszul complex is

𝒪(M) (f1,...,fr) 𝒪(M)r    𝒪(M)r (f1,...,fr) 𝒪(M).

The cokernel of the last map is again functions on the zero locus f1 = ... = fr = 0. It is the tensor product of the r many Koszul complexes for fi = 0, so its dimensions are given by binomial coefficients.

In pictures: given functions si, how do we define the locus where they all vanish?

In algebraic geometry, the ring of functions of the zero locus is A/(s1, ..., sr). In derived algebraic geometry, the dg ring of functions is the Koszul complex. If the loci si = 0 intersect transversely, these are equivalent.

Thus: Koszul complexes are derived intersections of zero loci.

Properties

Algebra structure

First, the Koszul complex Ks of (A,s) is a chain complex: the composition of any two maps is zero. Second, the map

KsKs  Ks            (α1αk)(β1β)  α1αkβ1β

makes it into a dg algebra.[1]

As a tensor product

The Koszul complex is a tensor product: if s = (s1, ..., sr), then

Ks  Ks1Ksr

where ⊗ denotes the derived tensor product of chain complexes of A-modules.[2]

Vanishing in regular case

When s1, ..., sr form a regular sequence, Ks → A/(s1, ..., sr) is a quasi-isomorphism, i.e.

Hi(Ks) = 0,i0,

and as for any s, H0(Ks) = A/(s1, ..., sr).

History

The Koszul complex was first introduced to define a cohomology theory for Lie algebras, by Jean-Louis Koszul (see Lie algebra cohomology). It turned out to be a useful general construction in homological algebra. As a tool, its homology can be used to tell when a set of elements of a (local) ring is an M-regular sequence, and hence it can be used to prove basic facts about the depth of a module or ideal which is an algebraic notion of dimension that is related to but different from the geometric notion of Krull dimension. Moreover, in certain circumstances, the complex is the complex of syzygies, that is, it tells you the relations between generators of a module, the relations between these relations, and so forth.

Detailed Definition

Let R be a commutative ring and E a free module of finite rank r over R. We write iE for the i-th exterior power of E. Then, given an R-linear map s:ER, the Koszul complex associated to s is the chain complex of R-modules:

K(s):0rEdrr1E1Ed1R0,

where the differential dk is given by: for any ei in E,

dk(e1ek)=i=1k(1)i+1s(ei)e1ei^ek.

The superscript ^ means the term is omitted. To show that dkdk+1=0, use the self-duality of a Koszul complex.

Note that 1E=E and d1=s. Note also that rER; this isomorphism is not canonical (for example, a choice of a volume form in differential geometry provides an example of such an isomorphism.)

If E=Rr (i.e., an ordered basis is chosen), then, giving an R-linear map s:RrR amounts to giving a finite sequence s1,,sr of elements in R (namely, a row vector) and then one sets K(s1,,sr)=K(s).

If M is a finitely generated R-module, then one sets:

K(s,M)=K(s)RM,

which is again a chain complex with the induced differential (d1M)(vm)=d(v)m.

The i-th homology of the Koszul complex

Hi(K(s,M))=ker(di1M)/im(di+11M)

is called the i-th Koszul homology. For example, if E=Rr and s=[s1sr] is a row vector with entries in R, then d11M is

s:MrM,(m1,,mr)s1m1++srmr

and so

H0(K(s,M))=M/(s1,,sr)M=R/(s1,,sr)RM.

Similarly,

Hr(K(s,M))={mM:s1m=s2m==srm=0}=HomR(R/(s1,,sr),M).

Koszul complexes in low dimensions

Given a commutative ring R, an element x in R, and an R-module M, the multiplication by x yields a homomorphism of R-modules,

MM.

Considering this as a chain complex (by putting them in degree 1 and 0, and adding zeros elsewhere), it is denoted by K(x,M). By construction, the homologies are

H0(K(x,M))=M/xM,H1(K(x,M))=AnnM(x)={mM,xm=0},

the annihilator of x in M. Thus, the Koszul complex and its homology encode fundamental properties of the multiplication by x. This chain complex K(x) is called the Koszul complex of R with respect to x, as in #Definition.

The Koszul complex for a pair (x,y)R2 is

0R d2 R2 d1 R0,

with the matrices d1 and d2 given by

d1=[xy] and
d2=[yx].

Note that di is applied on the left. The cycles in degree 1 are then exactly the linear relations on the elements x and y, while the boundaries are the trivial relations. The first Koszul homology H1(K(x, y)) therefore measures exactly the relations mod the trivial relations. With more elements the higher-dimensional Koszul homologies measure the higher-level versions of this.

In the case that the elements x1,x2,,xn form a regular sequence, the higher homology modules of the Koszul complex are all zero.

Example

If k is a field and X1,X2,,Xd are indeterminates and R is the polynomial ring k[X1,X2,,Xd], the Koszul complex K(Xi) on the Xi's forms a concrete free R-resolution of k.

Properties of a Koszul homology

Let E be a finite-rank free module over R, let s:ER be an R-linear map, and let t be an element of R. Let K(s,t) be the Koszul complex of (s,t):ERR.

Using k(ER)=i=0kkiEiR=kEk1E, there is the exact sequence of complexes:

0K(s)K(s,t)K(s)[1]0

where [-1] signifies the degree shift by -1 and dK(s)[1]=dK(s). One notes:[3] for (x,y) in kEk1E,

dK(s,t)((x,y))=(dK(s)x+ty,dK(s)[1]y).

In the language of homological algebra, the above means that K(s,t) is the mapping cone of t:K(s)K(s).

Taking the long exact sequence of homologies, we obtain:

Hi(K(s))tHi(K(s))Hi(K(s,t))Hi1(K(s))t.

Here, the connecting homomorphism

δ:Hi+1(K(s)[1])=Hi(K(s))Hi(K(s))

is computed as follows. By definition, δ([x])=[dK(s,t)(y)] where y is an element of K(s,t) that maps to x. Since K(s,t) is a direct sum, we can simply take y to be (0, x). Then the early formula for dK(s,t) gives δ([x])=t[x].

The above exact sequence can be used to prove the following.

Theorem — [4] Let R be a ring and M a module over it. If a sequence x1,x2,,xr of elements of R is a regular sequence on M, then

Hi(K(x1,,xr)M)=0

for all i1. In particular, when M = R, this is to say

0rRrdrr1Rr2Rrd2Rr[x1xr]RR/(x1,,xr)0

is exact; i.e., K(x1,,xr) is an R-free resolution of R/(x1,,xr).

Proof by induction on r. If r=1, then H1(K(x1;M))=AnnM(x1)=0. Next, assume the assertion is true for r - 1. Then, using the above exact sequence, one sees Hi(K(x1,,xr;M))=0 for any i2. The vanishing is also valid for i=1, since xris a nonzerodivisor on H0(K(x1,,xr1;M))=M/(x1,,xr1)M.

Corollary — [5] Let R, M be as above and x1,x2,,xn a sequence of elements of R. Suppose there are a ring S, an S-regular sequence y1,y2,,yn in S and a ring homomorphism SR that maps yi to xi. (For example, one can take S=[y1,,yn].) Then

Hi(K(x1,,xn)RM)=ToriS(S/(y1,,yn),M).

where Tor denotes the Tor functor and M is an S-module through SR.

Proof: By the theorem applied to S and S as an S-module, we see K(y1, ..., yn) is an S-free resolution of S/(y1, ..., yn). So, by definition, the i-th homology of K(y1,,yn)SM is the right-hand side of the above. On the other hand, K(y1,,yn)SM=K(x1,,xn)RM by the definition of the S-module structure on M.

Corollary — [6] Let R, M be as above and x1,x2,,xn a sequence of elements of R. Then both the ideal I=(x1,x2,,xn) and the annihilator of M annihilate

Hi(K(x1,,xn)M)

for all i.

Proof: Let S = R[y1, ..., yn]. Turn M into an S-module through the ring homomorphism SR, yixi and R an S-module through yi → 0. By the preceding corollary, Hi(K(x1,,xn)M)=ToriS(R,M) and then

AnnS(ToriS(R,M))AnnS(R)+AnnS(M)(y1,,yn)+AnnR(M)+(y1x1,...,ynxn).

For a local ring, the converse of the theorem holds. More generally,

Theorem — [7] Let R be a ring and M a nonzero finitely generated module over R . If x1, x2, ..., xr are elements of the Jacobson radical of R, then the following are equivalent:

  1. The sequence x1,,xr is a regular sequence on M,
  2. H1(K(x1,,xr)M)=0,
  3. Hi(K(x1,,xr)M)=0 for all i ≥ 1.

Proof: We only need to show 2. implies 1., the rest being clear. We argue by induction on r. The case r = 1 is already known. Let x' denote x1, ..., xr-1. Consider

H1(K(x;M))xrH1(K(x;M))H1(K(x1,,xr;M))=0M/xMxr.

Since the first xr is surjective, N=xrN with N=H1(K(x;M)). By Nakayama's lemma, N=0 and so x' is a regular sequence by the inductive hypothesis. Since the second xr is injective (i.e., is a nonzerodivisor), x1,,xr is a regular sequence. (Note: by Nakayama's lemma, the requirement M/(x1,,xr)M0 is automatic.)

Tensor products of Koszul complexes

In general, if C, D are chain complexes, then their tensor product CD is the chain complex given by

(CD)n=i+j=nCiDj

with the differential: for any homogeneous elements x, y,

dCD(xy)=dC(x)y+(1)|x|xdD(y)

where |x| is the degree of x.

This construction applies in particular to Koszul complexes. Let E, F be finite-rank free modules, and let s:ER and t:FR be two R-linear maps. Let K(s,t) be the Koszul complex of the linear map (s,t):EFR. Then, as complexes,

K(s,t)K(s)K(t).

To see this, it is more convenient to work with an exterior algebra (as opposed to exterior powers). Define the graded derivation of degree 1

ds:EE

by requiring: for any homogeneous elements x, y in ΛE,

  • ds(x)=s(x) when |x|=1
  • ds(xy)=ds(x)y+(1)|x|xds(y)

One easily sees that dsds=0 (induction on degree) and that the action of ds on homogeneous elements agrees with the differentials in #Definition.

Now, we have (EF)=EF as graded R-modules. Also, by the definition of a tensor product mentioned in the beginning,

dK(s)K(t)(e1+1f)=dK(s)(e)1+1dK(t)(f)=s(e)+t(f)=dK(s,t)(e+f).

Since dK(s)K(t) and dK(s,t) are derivations of the same type, this implies dK(s)K(t)=dK(s,t).

Note, in particular,

K(x1,x2,,xr)K(x1)K(x2)K(xr).

The next proposition shows how the Koszul complex of elements encodes some information about sequences in the ideal generated by them.

Proposition — Let R be a ring and I = (x1, ..., xn) an ideal generated by some n-elements. Then, for any R-module M and any elements y1, ..., yr in I,

Hi(K(x1,,xn,y1,,yr;M))i=j+kHj(K(x1,,xn;M))kRr.

where kRr is viewed as a complex with zero differential. (In fact, the decomposition holds on the chain-level).

Proof: (Easy but omitted for now)

As an application, we can show the depth-sensitivity of a Koszul homology. Given a finitely generated module M over a ring R, by (one) definition, the depth of M with respect to an ideal I is the supremum of the lengths of all regular sequences of elements of I on M. It is denoted by depth(I,M). Recall that an M-regular sequence x1, ..., xn in an ideal I is maximal if I contains no nonzerodivisor on M/(x1,,xn)M.

The Koszul homology gives a very useful characterization of a depth.

Theorem (depth-sensitivity) — Let R be a Noetherian ring, x1, ..., xn elements of R and I = (x1, ..., xn) the ideal generated by them. For a finitely generated module M over R, if, for some integer m,

Hi(K(x1,,xn)M)=0 for all i > m,

while

Hm(K(x1,,xn)M)0,

then every maximal M-regular sequence in I has length n - m (in particular, they all have the same length). As a consequence,

depth(I,M)=nm.

Proof: To lighten the notations, we write H(-) for H(K(-)). Let y1, ..., ys be a maximal M-regular sequence in the ideal I; we denote this sequence by y_. First we show, by induction on l, the claim that Hi(y_,x1,,xl;M) is AnnM/y_M(x1,,xl) if i=l and is zero if i>l. The basic case l=0 is clear from #Properties of a Koszul homology. From the long exact sequence of Koszul homologies and the inductive hypothesis,

Hl(y_,x1,,xl;M)=ker(xl:AnnM/y_M(x1,,xl1)AnnM/y_M(x1,,xl1)),

which is AnnM/y_M(x1,,xl). Also, by the same argument, the vanishing holds for i>l. This completes the proof of the claim.

Now, it follows from the claim and the early proposition that Hi(x1,,xn;M)=0 for all i > n - s. To conclude n - s = m, it remains to show that it is nonzero if i = n - s. Since y_ is a maximal M-regular sequence in I, the ideal I is contained in the set of all zerodivisors on M/y_M, the finite union of the associated primes of the module. Thus, by prime avoidance, there is some nonzero v in M/y_M such that I𝔭=AnnR(v), which is to say,

0vAnnM/y_M(I)Hn(x1,,xn,y_;M)=Hns(x1,,xn;M)sRs.

Self-duality

There is an approach to a Koszul complex that uses a cochain complex instead of a chain complex. As it turns out, this results essentially in the same complex (the fact known as the self-duality of a Koszul complex).

Let E be a free module of finite rank r over a ring R. Then each element e of E gives rise to the exterior left-multiplication by e:

le:kEk+1E,xex.

Since ee=0, we have: lele=0; that is,

0R1e1Ele2ErE0

is a cochain complex of free modules. This complex, also called a Koszul complex, is a complex used in (Eisenbud 1995). Taking the dual, there is the complex:

0(rE)*(r1E)*(2E)*(1E)*R0.

Using an isomorphism kE(rkE)*rk(E*), the complex (E,le) coincides with the Koszul complex in the definition.

Use

The Koszul complex is essential in defining the joint spectrum of a tuple of commuting bounded linear operators in a Banach space.[citation needed]

See also

  • Koszul–Tate complex
  • Syzygy (mathematics)

Notes

  1. The Stacks Project, section 0601
  2. The Stacks Project, section 0601, Lemma 15.28.12
  3. Indeed, by linearity, we can assume (x,y)=(e1+ϵ)e2ekk(ER) where RRϵER. Then
    dK(s,t)((x,y))=(s(e1)+t)e2ek+i=2k(1)i+1s(ei)(e1+ϵ)e2ei^ek,
    which is (dK(s)x+ty,dK(s)y).
  4. Matsumura 1989, Theorem 16.5. (i)
  5. Eisenbud 1995, Exercise 17.10.
  6. Serre 1975, Ch IV, A § 2, Proposition 4.
  7. Matsumura 1989, Theorem 16.5. (ii)

References

  • Eisenbud, David (1995). Commutative algebra: with a view toward algebraic geometry. Graduate Texts in Mathematics. 150. New York: Springer. ISBN 0-387-94268-8. 
  • William Fulton (1998), Intersection theory, Ergebnisse der Mathematik und ihrer Grenzgebiete. 3. Folge., 2 (2nd ed.), Berlin, New York: Springer-Verlag, ISBN 978-3-540-62046-4 
  • Matsumura, Hideyuki (1989), Commutative Ring Theory, Cambridge Studies in Advanced Mathematics (2nd ed.), Cambridge University Press, ISBN 978-0-521-36764-6 
  • Serre, Jean-Pierre (1975) (in French), Algèbre locale, Multiplicités, Cours au Collège de France, 1957–1958, rédigé par Pierre Gabriel. Troisième édition, 1975. Lecture Notes in Mathematics, 11, Berlin, New York: Springer-Verlag 
  • The Stacks Project, section 0601