Engel's theorem

From HandWiki
Short description: Theorem in Lie representation theory

In representation theory, a branch of mathematics, Engel's theorem states that a finite-dimensional Lie algebra 𝔤 is a nilpotent Lie algebra if and only if for each X𝔤, the adjoint map

ad(X):𝔤𝔤,

given by ad(X)(Y)=[X,Y], is a nilpotent endomorphism on 𝔤; i.e., ad(X)k=0 for some k.[1] It is a consequence of the theorem, also called Engel's theorem, which says that if a Lie algebra of matrices consists of nilpotent matrices, then the matrices can all be simultaneously brought to a strictly upper triangular form. Note that if we merely have a Lie algebra of matrices which is nilpotent as a Lie algebra, then this conclusion does not follow (i.e. the naïve replacement in Lie's theorem of "solvable" with "nilpotent", and "upper triangular" with "strictly upper triangular", is false; this already fails for the one-dimensional Lie subalgebra of scalar matrices).

The theorem is named after the mathematician Friedrich Engel, who sketched a proof of it in a letter to Wilhelm Killing dated 20 July 1890 (Hawkins 2000). Engel's student K.A. Umlauf gave a complete proof in his 1891 dissertation, reprinted as (Umlauf 2010).

Statements

Let 𝔤𝔩(V) be the Lie algebra of the endomorphisms of a finite-dimensional vector space V and 𝔤𝔤𝔩(V) a subalgebra. Then Engel's theorem states the following are equivalent:

  1. Each X𝔤 is a nilpotent endomorphism on V.
  2. There exists a flag V=V0V1Vn=0,codimVi=i such that 𝔤ViVi+1; i.e., the elements of 𝔤 are simultaneously strictly upper-triangulizable.

Note that no assumption on the underlying base field is required.

We note that Statement 2. for various 𝔤 and V is equivalent to the statement

  • For each nonzero finite-dimensional vector space V and a subalgebra 𝔤𝔤𝔩(V), there exists a nonzero vector v in V such that X(v)=0 for every X𝔤.

This is the form of the theorem proven in #Proof. (This statement is trivially equivalent to Statement 2 since it allows one to inductively construct a flag with the required property.)

In general, a Lie algebra 𝔤 is said to be nilpotent if the lower central series of it vanishes in a finite step; i.e., for C0𝔤=𝔤,Ci𝔤=[𝔤,Ci1𝔤] = (i+1)-th power of 𝔤, there is some k such that Ck𝔤=0. Then Engel's theorem implies the following theorem (also called Engel's theorem): when 𝔤 has finite dimension,

  • 𝔤 is nilpotent if and only if ad(X) is nilpotent for each X𝔤.

Indeed, if ad(𝔤) consists of nilpotent operators, then by 1. 2. applied to the algebra ad(𝔤)𝔤𝔩(𝔤), there exists a flag 𝔤=𝔤0𝔤1𝔤n=0 such that [𝔤,𝔤i]𝔤i+1. Since Ci𝔤𝔤i, this implies 𝔤 is nilpotent. (The converse follows straightforwardly from the definition.)

Proof

We prove the following form of the theorem:[2] if 𝔤𝔤𝔩(V) is a Lie subalgebra such that every X𝔤 is a nilpotent endomorphism and if V has positive dimension, then there exists a nonzero vector v in V such that X(v)=0 for each X in 𝔤.

The proof is by induction on the dimension of 𝔤 and consists of a few steps. (Note the structure of the proof is very similar to that for Lie's theorem, which concerns a solvable algebra.) The basic case is trivial and we assume the dimension of 𝔤 is positive.

Step 1: Find an ideal 𝔥 of codimension one in 𝔤.

This is the most difficult step. Let 𝔥 be a maximal (proper) subalgebra of 𝔤, which exists by finite-dimensionality. We claim it is an ideal of codimension one. For each X𝔥, it is easy to check that (1) ad(X) induces a linear endomorphism 𝔤/𝔥𝔤/𝔥 and (2) this induced map is nilpotent (in fact, ad(X) is nilpotent as X is nilpotent; see Jordan decomposition in Lie algebras). Thus, by inductive hypothesis applied to the Lie subalgebra of 𝔤𝔩(𝔤/𝔥) generated by ad(𝔥), there exists a nonzero vector v in 𝔤/𝔥 such that ad(X)(v)=0 for each X𝔥. That is to say, if v=[Y] for some Y in 𝔤 but not in 𝔥, then [X,Y]=ad(X)(Y)𝔥 for every X𝔥. But then the subspace 𝔥𝔤 spanned by 𝔥 and Y is a Lie subalgebra in which 𝔥 is an ideal of codimension one. Hence, by maximality, 𝔥=𝔤. This proves the claim.

Step 2: Let W={vV|X(v)=0,X𝔥}. Then 𝔤 stabilizes W; i.e., X(v)W for each X𝔤,vW.

Indeed, for Y in 𝔤 and X in 𝔥, we have: X(Y(v))=Y(X(v))+[X,Y](v)=0 since 𝔥 is an ideal and so [X,Y]𝔥. Thus, Y(v) is in W.

Step 3: Finish up the proof by finding a nonzero vector that gets killed by 𝔤.

Write 𝔤=𝔥+L where L is a one-dimensional vector subspace. Let Y be a nonzero vector in L and v a nonzero vector in W. Now, Y is a nilpotent endomorphism (by hypothesis) and so Yk(v)0,Yk+1(v)=0 for some k. Then Yk(v) is a required vector as the vector lies in W by Step 2.

See also

Notes

Citations

  1. Fulton & Harris 1991, Exercise 9.10..
  2. Fulton & Harris 1991, Theorem 9.9..

Works cited